Practica Nº 5 Diseño de circuitos
combinacionales.
Preparatorio:
I.
Diseñe
un circuito combinacional que permita la conversión de un número BCD a su
correspondiente número binario de cuatro bits.
BCD
|
BINARIO
|
|||||||
E
|
D
|
C
|
B
|
A
|
Z
|
Y
|
X
|
W
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
0
|
0
|
0
|
0
|
1
|
1
|
0
|
0
|
1
|
1
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
0
|
0
|
0
|
0
|
1
|
0
|
1
|
0
|
1
|
0
|
1
|
0
|
0
|
1
|
1
|
0
|
0
|
1
|
1
|
0
|
0
|
0
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
0
|
1
|
0
|
0
|
0
|
1
|
0
|
0
|
0
|
0
|
1
|
0
|
0
|
1
|
1
|
0
|
0
|
1
|
0
|
1
|
0
|
1
|
0
|
X
|
x
|
X
|
X
|
0
|
1
|
0
|
1
|
1
|
X
|
X
|
X
|
X
|
0
|
1
|
1
|
0
|
0
|
X
|
X
|
X
|
X
|
0
|
1
|
1
|
0
|
1
|
X
|
X
|
X
|
X
|
0
|
1
|
1
|
1
|
0
|
X
|
X
|
X
|
X
|
0
|
1
|
1
|
1
|
1
|
x
|
X
|
x
|
X
|
1
|
0
|
0
|
0
|
0
|
1
|
0
|
1
|
0
|
1
|
0
|
0
|
0
|
1
|
1
|
0
|
1
|
1
|
1
|
0
|
0
|
1
|
0
|
1
|
1
|
0
|
0
|
1
|
0
|
0
|
1
|
1
|
1
|
1
|
0
|
1
|
1
|
0
|
1
|
0
|
0
|
1
|
1
|
1
|
0
|
1
|
0
|
1
|
0
|
1
|
1
|
1
|
1
|
1
|
1
|
0
|
1
|
1
|
0
|
X
|
x
|
X
|
X
|
1
|
0
|
1
|
1
|
1
|
X
|
X
|
X
|
X
|
1
|
1
|
0
|
0
|
0
|
X
|
X
|
X
|
X
|
1
|
1
|
0
|
0
|
1
|
X
|
X
|
X
|
X
|
1
|
1
|
0
|
1
|
0
|
X
|
X
|
X
|
X
|
1
|
1
|
0
|
1
|
1
|
x
|
X
|
x
|
X
|
1
|
1
|
1
|
0
|
0
|
X
|
x
|
X
|
X
|
1
|
1
|
1
|
0
|
1
|
X
|
X
|
X
|
X
|
1
|
1
|
1
|
1
|
0
|
X
|
X
|
X
|
X
|
1
|
1
|
1
|
1
|
1
|
X
|
X
|
X
|
X
|
|
|
C’B’A’
|
C’B’A
|
C’BA’
|
C’BA
|
CB’A’
|
CB’A
|
CBA’
|
CBA
|
|
|
000
|
001
|
010
|
011
|
100
|
101
|
110
|
111
|
E’D’
|
00
|
|
|
|
|
|
|
|
|
E’D
|
01
|
1
|
1
|
X
|
X
|
X
|
X
|
X
|
X
|
ED’
|
10
|
|
|
1
|
1
|
1
|
1
|
X
|
X
|
ED
|
11
|
X
|
X
|
X
|
X
|
X
|
X
|
X
|
X
|
Z= E’D+ E=E+D
|
|
C’B’A’
|
C’B’A
|
C’BA’
|
C’BA
|
CB’A’
|
CB’A
|
CBA’
|
CBA
|
|
|
000
|
001
|
010
|
011
|
100
|
101
|
110
|
111
|
E’D’
|
00
|
|
|
|
|
1
|
1
|
1
|
1
|
E’D
|
01
|
|
|
X
|
X
|
X
|
X
|
X
|
X
|
ED’
|
10
|
|
|
1
|
1
|
1
|
1
|
X
|
X
|
ED
|
11
|
X
|
X
|
X
|
X
|
X
|
X
|
X
|
X
|
Y=C+EC’B=EB+C
|
|
C’B’A’
|
C’B’A
|
C’BA’
|
C’BA
|
CB’A’
|
CB’A
|
CBA’
|
CBA
|
|
|
000
|
001
|
010
|
011
|
100
|
101
|
110
|
111
|
E’D’
|
00
|
|
|
1
|
1
|
|
|
1
|
1
|
E’D
|
01
|
|
|
X
|
X
|
X
|
X
|
X
|
X
|
ED’
|
10
|
1
|
1
|
|
|
1
|
1
|
X
|
X
|
ED
|
11
|
X
|
X
|
X
|
X
|
X
|
X
|
X
|
X
|
X=
E’B+B’E=EB
|
|
C’B’A’
|
C’B’A
|
C’BA’
|
C’BA
|
CB’A’
|
CB’A
|
CBA’
|
CBA
|
|
|
000
|
001
|
010
|
011
|
100
|
101
|
110
|
111
|
E’D’
|
00
|
|
1
|
|
1
|
|
1
|
|
1
|
E’D
|
01
|
|
1
|
X
|
X
|
X
|
X
|
X
|
X
|
ED’
|
10
|
|
1
|
|
1
|
|
1
|
X
|
X
|
ED
|
11
|
X
|
X
|
X
|
X
|
X
|
X
|
X
|
X
|
W=
C’B’A+ C’BA +CB’A+ CBA=A(C’B’+C’B+ CB’+CB)= A(C’ + C)= A
II.
Diseñe
un circuito combinacional que permita la conversión de un número binario a su equivalente
en código GRAY de cuatro bits.
BINARIO
|
GRAY
|
||||||
A
|
B
|
C
|
D
|
W
|
X
|
Y
|
Z
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
1
|
0
|
0
|
1
|
1
|
0
|
0
|
1
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
1
|
0
|
0
|
1
|
0
|
1
|
0
|
1
|
1
|
1
|
0
|
1
|
1
|
0
|
0
|
1
|
0
|
1
|
0
|
1
|
1
|
1
|
0
|
1
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
1
|
0
|
0
|
1
|
0
|
0
|
1
|
1
|
1
|
0
|
1
|
1
|
0
|
1
|
0
|
1
|
1
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
1
|
1
|
0
|
1
|
1
|
0
|
0
|
1
|
0
|
1
|
0
|
1
|
1
|
0
|
1
|
1
|
0
|
1
|
1
|
1
|
1
|
1
|
0
|
1
|
0
|
0
|
1
|
1
|
1
|
1
|
1
|
1
|
0
|
0
|
0
|
|
|
C’D’
|
C’D
|
CD’
|
CD
|
|
|
00
|
01
|
10
|
11
|
A’B’
|
00
|
|
|
|
|
A’B
|
01
|
|
|
|
|
AB’
|
10
|
1
|
1
|
1
|
1
|
AB
|
11
|
1
|
1
|
1
|
1
|
W=A
|
|
C’D’
|
C’D
|
CD’
|
CD
|
|
|
00
|
01
|
11
|
10
|
A’B’
|
00
|
|
|
|
|
A’B
|
01
|
1
|
1
|
1
|
1
|
AB
|
11
|
|
|
|
|
AB’
|
10
|
1
|
1
|
1
|
1
|
X=A’B+AB’=AB
|
|
C’D’
|
C’D
|
CD
|
CD’
|
|
|
00
|
01
|
11
|
10
|
A’B’
|
00
|
|
|
1
|
1
|
A’B
|
01
|
1
|
1
|
|
|
AB
|
11
|
1
|
1
|
|
|
AB’
|
10
|
|
|
1
|
1
|
Y=BC’+B’C=BC
|
|
C’D’
|
C’D
|
CD
|
CD’
|
|
|
00
|
01
|
11
|
10
|
A’B’
|
00
|
0
|
1
|
0
|
1
|
A’B
|
01
|
0
|
1
|
0
|
1
|
AB
|
11
|
0
|
1
|
0
|
1
|
AB’
|
10
|
0
|
1
|
0
|
1
|
Z= C’D+ CD’=CD
III.
El
funcionamiento de un motor permite abrir o cerrar una puerta automática cuando
a la salida de un circuito digital se obtiene un nivel alto. La señal de salida
controlada por un circuito, tiene cuatro entradas:
A=
orden de encender el motor, se activa en alto.
B=
orden de deshabilitar el funcionamiento del motor, se activa en bajo.
C=
orden de emergencia, activa en alto.
D=
salida de un sensor de presencia, en nivel alto significa que una persona está
cerca a la puerta.
El
motor debe encenderse cuando: exista la orden de encendido o en caso de que una
persona se encuentre cercana y no haya orden de deshabilitar el motor; excepto
si hay emergencia, casó en la cual el motor se enciende independientemente de
otras señales.
A
|
B
|
C
|
D
|
X
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
0
|
1
|
0
|
0
|
1
|
1
|
1
|
0
|
1
|
0
|
0
|
0
|
0
|
1
|
0
|
1
|
1
|
0
|
1
|
1
|
0
|
1
|
0
|
1
|
1
|
1
|
1
|
1
|
0
|
0
|
0
|
0
|
1
|
0
|
0
|
1
|
0
|
1
|
0
|
1
|
0
|
1
|
1
|
0
|
1
|
1
|
1
|
1
|
1
|
0
|
0
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
1
|
1
|
1
|
|
|
C’D’
|
C’D
|
CD
|
CD’
|
|
|
00
|
01
|
11
|
10
|
A’B’
|
00
|
|
|
1
|
1
|
A’B
|
01
|
|
1
|
1
|
1
|
AB
|
11
|
1
|
1
|
1
|
1
|
AB’
|
10
|
|
|
1
|
1
|
X=C+DB+AB=C+(A+D)B
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